Php Leap Year

Syntax

bool checkLeapYear(int $year)

Example

<?php
function checkLeapYear($year){
    return (($year % 4 == 0) && ($year % 100 != 0)) || ($year % 400 == 0);
}

if(checkLeapYear(2024)){
    echo "2024 is a Leap Year";
} else {
    echo "2024 is not a Leap Year";
}
?>

Output

2024 is a Leap Year

Explanation

In the above code, we have created a function named checkLeapYear() that takes a year as a parameter. Inside the function, we have used the formula to check if a year is a leap year or not.

(($year % 4 == 0) && ($year % 100 != 0)) || ($year % 400 == 0)

The first part of the formula checks if the year is divisible by 4 and not divisible by 100. If this is true, then the year is a leap year. The second part of the formula checks if the year is divisible by 400. If this is true, then the year is a leap year.

Use

This function is used to determine whether a given year is a leap year or not in PHP.

Important Points

• A leap year is a year that is divisible by 4, but not by 100, unless it is divisible by 400.
• The checkLeapYear() function returns a boolean value (true/false) based on whether a given year is a leap year or not.
• This function can be used in various date and time based applications.

Summary

• In this tutorial, we learned how to create a function to check if a year is a leap year or not in PHP.
• The checkLeapYear() function returns a true or false value based on whether a given year is a leap year or not.
• Leap year calculations are important in date and time applications and form an important part of calendar systems.